thornhappy
Posts: 8596
Joined: 12/16/2006 Status: offline
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quote:
ORIGINAL: MiGTeK Bearing in mind that i'm half way through my second year of this stuff: v = I x R, therefore: 4.7x10^-3 (assuming you meant milliohms, not megohms) x .250A = 1.175mV.. so not a whole lot. <edit> Oh, wait. you said microamps. That'd make it 1.175 microvolts. my bad. 100mW of power being consumed at a constant rate will result in a total of 2.4 W/h in a 24 hour period, i can't remember what the conversion rate between watthours and joules is, and i'm not going to revert to cheating by checkin on wiki. I have no idea. Never heard of it. This one i've covered, but forgotten, and it's not something i do every day. If memory serves, the impedance at resonance is very low for non-resistive components, thus the impedance overall would be very close to 80 ohms. These almost sound more electronicy than electrickery, but, i guess, it's all very similar... I'm just used to dealing with 240/415 volt and hundreds of watts/amps. I know, I'm late to the thread... Thevenin's Theorem (roughly) states that a circuit consisting of voltage sources and resistors may be represented by an ideal voltage source and a (series) ideal resistor. Yep, I could solve them but had to get the definition from Wiki. You were right, the impedance is 80 ohms at resonance. ta ta thornhappy
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