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RE: A little geometry problem - 10/31/2008 12:15:54 AM

persephonee

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hehe....i just got off the phone with my man....hes moving on.....SUNDAY...which means that he needs to beat the ever living crap outta me on Saturday...which means that this girl is going to call in sick to work for my night shift...wonder what illness i can come up with.....

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Post #: 21

RE: A little geometry problem - 10/31/2008 12:27:11 AM

GreedyTop

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sprained ankle? slipping when you got outta the tub?

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Post #: 22

RE: A little geometry problem - 10/31/2008 12:33:05 AM

MadAxeman

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If you have a male boss, just say 'female things' then start to go into detail...

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Post #: 23

RE: A little geometry problem - 10/31/2008 12:34:02 AM

persephonee

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that might work...but then i would have to remember to limp on the correct side...betcha if i get beaten only on one side that would help with that....good thinkin.

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Post #: 24

RE: A little geometry problem - 10/31/2008 12:38:25 AM

GreedyTop

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I like MA's idea too... or MIGRAINE associated with girly stuff......

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Post #: 25

RE: A little geometry problem - 10/31/2008 12:50:13 AM

persephonee

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my bosses are women...and they know that nothing female happens on a saturday that doenst involve orgasm. Axey...i wishes you were my boss....sniffle.

nite all....i just remembered that i get to go trick or treating tomorrow.....im tired already...

kisses

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And You can carry me away....if You want to. ~Kasey Chambers

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Post #: 26

RE: A little geometry problem - 10/31/2008 12:52:03 AM

GreedyTop

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*adoresPers* get an Ace bandage, wrap it around an ankle.. then you'll remember which ankle you've sprained :D

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Post #: 27

RE: A little geometry problem - 10/31/2008 12:58:57 AM

blacksword404

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quote:

ORIGINAL: GreedyTop

*adoresPers* get an Ace bandage, wrap it around an ankle.. then you'll remember which ankle you've sprained :D

I sprained my ankle yesterday on my way to the gym. Lucky for me it was the left foot.

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Post #: 28

RE: A little geometry problem - 10/31/2008 1:03:29 AM

GreedyTop

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quote:

ORIGINAL: blacksword404

quote:

ORIGINAL: GreedyTop

*adoresPers* get an Ace bandage, wrap it around an ankle.. then you'll remember which ankle you've sprained :D

I sprained my ankle yesterday on my way to the gym. Lucky for me it was the left foot.

clutch foot? bad!

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Post #: 29

RE: A little geometry problem - 10/31/2008 1:15:10 AM

blacksword404

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quote:

ORIGINAL: GreedyTop

quote:

ORIGINAL: blacksword404

quote:

ORIGINAL: GreedyTop

*adoresPers* get an Ace bandage, wrap it around an ankle.. then you'll remember which ankle you've sprained :D

I sprained my ankle yesterday on my way to the gym. Lucky for me it was the left foot.

clutch foot? bad!

Not as bad as if it was the throttle and brake foot. I float so i'm good. As long as i can still press the clutch in i won't worry about the pain.

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Ego sum erus.

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Post #: 30

RE: A little geometry problem - 10/31/2008 1:19:20 AM

GreedyTop

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clutches are for stops and starts....throttle and brake are easy... suck it up, driver ;)

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Post #: 31

RE: A little geometry problem - 10/31/2008 3:00:55 AM

seeksfemslave

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quote:

ORIGINAL: CalifChick
In a right triangle that is also an isosceles triangle, the hypotenuse equals the length of the leg times the square root of 2.

So the hypotenuse, which is "one day" (1) is equal to the unknown length (U) times the square root of 2.

1 = U x (square root of 2)
1 = U x (1.189)
1/1.189 = U
.84 = U
The unknown length is .84 of a day, or 20.16 hours.
Cali

Sq root of 2 = 1.414 my little chickedeee
1.189 is nearly equal to the sq root of 1.414....how odd

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Post #: 32

RE: A little geometry problem - 10/31/2008 3:48:59 AM

ShiftedJewel

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Oh Gawd... now my head hurts!!

Waaaaaaaaaaay to early for this.

Jewel

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Post #: 33

RE: A little geometry problem - 10/31/2008 5:26:53 AM

candystripper

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Unless I'm missing something, A walked the distance he could cover in two days...whatever the hell that is.

How is it you 'needed' an answer to this?

P.S. Whoops....didn't bother to read the whole thread first...okay, so you needed to get the math down for a story....but still, seems like a silly problem to me unless A truely can walk for a whole day, in a straight line, and then repeat his pace exactly on day two. Maybe I'm just dense.

candystripper

< Message edited by candystripper -- 10/31/2008 5:42:32 AM >

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Post #: 34

RE: A little geometry problem - 10/31/2008 5:34:50 AM

Dnomyar

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Wait there was not enough information for that question. Are the 2 people basketball playeres with long legs. Are the 2 people midgets with short legs. Is one person a basketball player and the other a midget. Are they both walking on crutches or is only one walking on a crutch. Does the one walking on a crutch have long or short legs. Are they both going up hill or down hill. Is one of them going up hill while the other goes down hill. How old are they. Do they have walkers?

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Post #: 35

RE: A little geometry problem - 10/31/2008 6:13:01 AM

UncleNasty

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Joined: 3/20/2004
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quote:

ORIGINAL: GreedyTop

SPAAAAAAAAARRRRRRRRRRRRRRRRRRRRRRRKLIEEEEEEEEEEEEEEEEEEEESSSSSSSSSS!!!!!!!!!!!!!!!!!!!

Now that's cute.

Uncle Nasty

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Post #: 36

RE: A little geometry problem - 10/31/2008 6:47:44 AM

xxblushesxx

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Joined: 11/3/2005
From: Kentucky
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quote:

ORIGINAL: MadAxeman

So it's a thrilling story of our hero being followed by an assailant on a piece of graph paper?
Why can't he hide behind a feckn tree like a regular person?

*giggles*

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Post #: 37

RE: A little geometry problem - 10/31/2008 8:25:09 AM

CalifChick

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quote:

ORIGINAL: CalifChick
1 = U x (square root of 2)
1 = U x (1.189)
1/1.189 = U
.84 = U

The unknown length is .84 of a day, or 20.16 hours.

Apparently I hit the "squareroot" function twice on my calculator. The sqrt of 2 is 1.414, not 1.189. U = .70 of a day, or 16.8 hours.

And go right 45 degrees then left 45 degrees doesn't make you parallel to the other plane of travel. Think of it like the mirror image of a capital N. The first guy goes straight up, the second guy is the slanted line. If he turned back 45 degrees, then he would be on a new slanted line (A is red and B is black):

|\
|/

If you turn 90 degrees to the right, then 90 degrees to the either direction, you become parallel with the other guy, but ONLY because 90+90 = 180, the angle of a line, and not because you turned back the same number of degrees:

|
|__|

Cali

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Post #: 38

RE: A little geometry problem - 10/31/2008 8:52:59 AM

Termyn8or

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Calif, that's what I thought in a way, but the wording of the question is not quite clear.

"Apparently I hit the "squareroot" function twice on my calculator. The sqrt of 2 is 1.414, not 1.189. U = .70 of a day, or 16.8 hours. "

In your calculation U would be more accurately defined as .70711, therefore should be rounded up to .71 if one wants to only use two figures. But you seem to have seen it the way I saw it before I reread it.

First of all it was never said the person who walked straight walked a day, however, no matter what the trig figures out, if they walk at equal speed their paths might intersect, but they should never meet assuming one condition.

If the second person turned and was heading towards the reference path they would have had to turn 90 degrees to the left. In that case the second person walks a longer path to get back to the straight line, and it is longer by 1.4142 times. That is the original .70711 doubled, considering each side of the isoceles to be a right triangle.

What the OP actually said was turned 45 degrees, and as another pointed out, that would make their paths paralell. That would of course make the answer infinity.

That .70711 is like a magic number, it's where sine and cosine meet. Anything dealing with triangles can always be dealt with on the short end of the scale, or table. I used it alot in electronics years ago and when I was racing around like a crazy hoodlum (wait, I was a crazy hoodlum), I wanted to calculate G force in these fast cars I had. Had to sit there and convert MPH/H into FPS/S and then via vectors I would calculate the actual G force. I regret to report that rare is the car that can put you at 2 Gs. No matter how fast you think it is, it ain't. Just another piece of useless information I got just because I wanted it.

When I used to really have some spare time I got more. I don't want to go into all that right now but it has to do with very old computers, cars and machine shops.

T

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Post #: 39

RE: A little geometry problem - 10/31/2008 9:17:41 AM

SimplyMichael

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Cali has it right

quote:

If you turn 90 degrees to the right, then 90 degrees to the either direction, you become parallel with the other guy, but ONLY because 90+90 = 180, the angle of a line, and not because you turned back the same number of degrees:

Picture a protractor, the kind that is a half circle, the bottom is the "parallel line" and the half cirle is 180 degree arc.

(in reply to CalifChick)

Post #: 40

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