quote:

ORIGINAL: mnottertail

2256 and now its 3356 khz or some shit, you aint talking about increasing frequency.

quote:

ORIGINAL: mnottertail

quote:

Real0ne
Ohms law says that a light bulb will not light across a dead short...period.

I am so sick of your unknowing bullshit.   Ohms law doesn't say any goddamn thing as ridiculous as that.  

quote:

ORIGINAL: Politesub53

quote:

ORIGINAL: Real0ne

HUH?

does not apply? or that the correct answer could not be established simply through "ohms law"?

Ohms law says that a light bulb will not light across a dead short...period.
If you think it can then be my guest and bring your "ohms law" to the table and lets see how far you get with it..LOL

Where does Ohms law state that ? The potential difference across both terminals will vary depending on the load......

quote:



With nothing on the circuit or with a load on the circuit grabbing both rods did not shock anyone.

How many more times do you need the same fucking thing explained to you.

Dunno, how many more times shall I post the answer.

quote:

ORIGINAL: Politesub53

I`ll go one further. If you have a 415 volt suppy and 2 x 240v lamps, is it possible to wire the lamps up for normal use ?

You wouldnt think so but the answer, explained by Ohms Law, is wire them up in series, nor parallel.

quote:

ORIGINAL: dRGreen420

quote:

ORIGINAL: mnottertail

You prove it.

I already did.

I'm not going out of my way to be polite because you disagree with everything anyway, so I'm not going to waste my time being nice about it and spending time writing an essay that is going to be ignored and simply said to be wrong regardless of what is written. So you are having abrupt answers in which you are expected to know certain things. Not my fault if you don't.

You brought up the magic.

You are bulking everything together as one. Super luminal velocities measured in the resonant frequency of a coil has nothing to do with light bulbs.

quote:

ORIGINAL: mnottertail

a standing wave reinforces itself and gains amplitude, not frequency.

Yes. Frequency is not gained. You have been too busy arguing to be able to comprehend what I am talking about or even simple principles of physics. The resonant frequency is higher, the effective wavelength is shorter, according to the velocity of light as a limit such a high frequency is not possible, yet the higher frequency is measured. The reinforcement of amplitude occurs at an effectively shorter wavelength than the physical (full wave) length of the wire. Now as you earlier stated, due to burdens and not being in a vacuum, the effective wavelength should be longer, it "can't" be faster than light, the frequency "must" be lower. But it is higher, beyond 100% luminal. Repeatable, repeated, verifiable and verified, accessible for Joe Sixpack to test for himself and to see it with his own eyes. Very simple stuff. This is high school level physics.

quote:

ORIGINAL: dRGreen420

quote:

ORIGINAL: mnottertail

2256 and now its 3356 khz or some shit, you aint talking about increasing frequency.

Where did 3356 come from?

There is no magic. You simply energise a piece of wire via a signal generator/oscillator output connected to one end, the other end of the coil free. The negative/ground output of the signal gen is connected to a ground plane approx 60cm below the coil. As a quarter wave resonator the luminal frequency of the wire is calculated from 4 times the length, being the full wavelength. Bunched up the wave will be retarded, the measured frequency will be below the luminal frequency. Coiled in a 1:1 height to diameter ratio on a "hollow" frame, as Tesla's extra coil, this measured frequency goes beyond the luminal frequency. Up to 157% the velocity of light is possible in this way.

This, for example, is why the internet Tesla paradigm crew have no idea, when they have their long cylinder coils, the wire all being bunched together and in direct contact with other materials, no consideration of  anything except "more turns = bigger lightning bolts".

quote:

ORIGINAL: Real0ne

Like I said, he simply does not fucking get it and wants to be taught while kicking and screaming all the way to the dunce corner LOL

go to any dump peeps can pick up all the parts for 50 bucks tops to do both the hairpin and the coils.

quote:

ORIGINAL: mnottertail

No, exactly, it is high school level physics. has been said since the outset.

the resistance of a dead short is not 0 it is extremely high.  thats why it gets hot and melts and starts fires.  you know, like high school level physics.

And speaking of high school level physics, we now have an apparatus consisting of several parts, that  we can use to light a light bulb.  How convienient, but we already have that, and we dont need the apparatus plugged into the wall to light the lighbulb and consume Kwh of electricity to add to our bill.

Simple high school physics.

Other than that we got nothing here.

quote:

ORIGINAL: mnottertail

No, exactly, it is high school level physics. has been said since the outset.

the resistance of a dead short is not 0 it is extremely high. 

quote:

ORIGINAL: Politesub53


Ron beat me too it....... I am glad someone understands the basics.

quote:

ORIGINAL: Real0ne

quote:

ORIGINAL: Politesub53

quote:

ORIGINAL: Real0ne

HUH?

does not apply? or that the correct answer could not be established simply through "ohms law"?

Ohms law says that a light bulb will not light across a dead short...period.
If you think it can then be my guest and bring your "ohms law" to the table and lets see how far you get with it..LOL

Where does Ohms law state that ? The potential difference across both terminals will vary depending on the load......

quote:



With nothing on the circuit or with a load on the circuit grabbing both rods did not shock anyone.

How many more times do you need the same fucking thing explained to you.

Dunno, how many more times shall I post the answer.

the load is a dead short parallel with a bulb, the bulb lights even with a short across it.

finally starting to catch up LOL

quote:

ORIGINAL: Politesub53

I`ll go one further. If you have a 415 volt suppy and 2 x 240v lamps, is it possible to wire the lamps up for normal use ?

You wouldnt think so but the answer, explained by Ohms Law, is wire them up in series, nor parallel.

good so you seem to know the difference between series and parallel, now if you have a constant voltage 240v supply (which is what the power line is), is it possible to wire them up in parallel and get full brightness?

Then what happens when you replace one bulb with a short, hence shorting the other bulb?

feel free to answer the same question I just asked for the 10,000th time, why does the lamp light in the tesla circuit but not in yours

quote:

ORIGINAL: Politesub53

quote:

ORIGINAL: Real0ne

quote:

ORIGINAL: Politesub53

quote:

ORIGINAL: Real0ne

HUH?

does not apply? or that the correct answer could not be established simply through "ohms law"?

Ohms law says that a light bulb will not light across a dead short...period.
If you think it can then be my guest and bring your "ohms law" to the table and lets see how far you get with it..LOL

Where does Ohms law state that ? The potential difference across both terminals will vary depending on the load......

quote:



With nothing on the circuit or with a load on the circuit grabbing both rods did not shock anyone.

How many more times do you need the same fucking thing explained to you.

Dunno, how many more times shall I post the answer.

the load is a dead short parallel with a bulb, the bulb lights even with a short across it.

finally starting to catch up LOL

quote:

ORIGINAL: Politesub53

I`ll go one further. If you have a 415 volt suppy and 2 x 240v lamps, is it possible to wire the lamps up for normal use ?

You wouldnt think so but the answer, explained by Ohms Law, is wire them up in series, nor parallel.

good so you seem to know the difference between series and parallel, now if you have a constant voltage 240v supply (which is what the power line is), is it possible to wire them up in parallel and get full brightness?

Then what happens when you replace one bulb with a short, hence shorting the other bulb?

feel free to answer the same question I just asked for the 10,000th time, why does the lamp light in the tesla circuit but not in yours

Unsure why Im wasting my time but since you ask. If you change one lamp for a piece of wire, the other lamp will burn really bright for a second or two then explode. Thats because it now has 415v running through it.

If you think electricity wont flow through a dead short, how do you think a kettle works ? I dont know why Im having to explain the obvious to you.