CuriousLord
Posts: 3911
Joined: 4/3/2007 Status: offline
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Ohh, neat! You finally mentioned something more specific than "OMG ITS GOING TO BE POWERZED YO"! Let's do the math. :) Heat of Combustion (Hydrogen): 62,000 (BTU/lb) (Gross) -The Chemistry of Combustion in Plain English. Because I perfer SI over English units: 62,000 BTU/lb = 1.4 * 10^8 J/kg Therefore, for every kilogram of elemental Hydrogen you put into the cyclinder, you're going to get about 1.4*10^8 Joules of energy. Let's, for a moment, assume that the cyclinder's head interia comes to, for the same of arbitrary convinence, 1.4*10^7 kg. Assuming a friction coefficient of, being generous, 0.001, you're looking at an increase of 9.99 rotations per second in the turbine head. Next, how much is the generator going to put out? Half, at best. -Wikipedia. Note: This is very generous. This is the theorical best, not something we can actually achieve in real world mechanics. So, now you're back with 6.9(93) * 10^7 J in electricity. You can get, in a large scale environment under best conditions (again, what you're not going to get- I'm just being generous)- a 70% return of energy in Hydrogen. This means 4.8(951)*10^7 J. -HyWeb: Knowledge- Hydrogen in Energy Sector Chapter 3.* Going back to the orginial conversion, this equates to 0.34(965) kg Hydrogen. Again, being generous, and rounding up, 0.35 kg Hydrogen. You're going to get a return of 0.35 kg Hydrogen for every 1.00 kg Hydrogen you run through this system- 35%- at optimal efficiency. You're not going to make net hydrogen. *See just under '3.4.1 Present state of the art'. Edit: Added in a source.
< Message edited by CuriousLord -- 5/3/2007 10:31:32 PM >
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